Respuesta :

hoangngocgiaphuc

Answer:

go from inside out.

h(x)=x/3

[tex](\sqrt{2})^{3}[/tex]=> h(6) = 6/3 = 2

g(x) = [tex]\sqrt{x}[/tex]

=> g(h(6)) = g(2) = [tex]\sqrt{2}[/tex]

f(x) = [tex]x^{3}[/tex]

=> f(g(h(6))) = f([tex]\sqrt{2}[/tex] ) = [tex](\sqrt{2} )^{3}[/tex]

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