If Circle A has a radius that is five more than twice as long as the radius of circle B and the sum of the diameters of the circle is 88 inches, find the area and circumference of circle A

Respuesta :

Answer:

Circumference of a circle A = [tex]389.7 \,\,inches[/tex]

Area of a circle A = 12081.1 square inches

Step-by-step explanation:

Let [tex]r[/tex] denotes radius of circle B.

Circle A has a radius that is five more than twice as long as the radius of circle B.

So,

Radius of circle A = [tex]5+2r[/tex]

Diameter of circle = 2 (radius of circle)

So,

Diameter of circle B = 2r

Diameter of circle A = [tex]2(5+2r)[/tex]

Sum of the diameters of the circles A and B = [tex]2r+2(5+2r)[/tex]

                                                                         [tex]=2r+10+4r[/tex]

                                                                         [tex]=6r+10[/tex]

As sum of the diameters of the circles is 88 inches,

[tex]6r+10=88\\6r=78[/tex]

[tex]r=13[/tex] inches

Radius of a circle A = [tex]2(5+2r)[/tex]

                                [tex]=2[5+2(13)][/tex]

                                [tex]=2(5+26)[/tex]

                                [tex]=2(31)[/tex]

                                [tex]=62[/tex] inches

Let R denotes radius of a circle A.

R = 62 inches

Circumference of a circle [tex]=2\pi R=2\pi (62)=124\pi =124(\frac{22}{7})=389.7 \,\,inches[/tex]

Area of a circle [tex]=\pi r^2=\pi (62)^2=3844\pi=3844(\frac{22}{7})=12081.1[/tex] square inches