Respuesta :
Answer:
Total number of bottles Bar A get = 126
Total number of bottles Bar B get = 251
Total number of bottles Bar C get = 502
Step-by-step explanation:
Given - A distributor must distribute 879 bottles of beer among 3 bars. If the order of bar A is half that of bar B and a quarter of bar C.
To find - How many bottles do each bar get?
Proof -
Let us assume that
Total number of bottles Bar A get = x
Total number of bottles Bar B get = y
Total number of bottles Bar C get = z
Now,
Given that
Total bottles distributed = 879
⇒x + y + z = 879 ..............(1)
Now,
Given that, the order of bar A is half that of bar B and a quarter of bar C
⇒x = [tex]\frac{1}{2}y[/tex] , x = [tex]\frac{1}{4} z[/tex]
⇒y = 2x .............(2)
z = 4x ..............(3)
Now,
Put the values of y and z in equation (1), we get
x + 2x + 4x = 879
⇒7x = 879
⇒x = [tex]\frac{879}{7}[/tex] = 125.57
⇒y = 2(125.57) = 251.14
⇒z = 4(125.57) = 502.28
∴ we get
Total number of bottles Bar A get = x = 125.57 ≈ 126
Total number of bottles Bar B get = y = 251.14 ≈ 251
Total number of bottles Bar C get = z = 502.28 ≈ 502
