*Geometry* Need help, will give brainliest

Answer:
[tex]sinC = \frac{7}{25}\\~\\cosC = \frac{24}{25}\\~\\tanC = \frac{7}{24}[/tex]
Step-by-step explanation:
To get the sine of a non-right angle C in a right triangle, just divide the side opposing C by the long side. To get the cosine, divide the sides at C (shorter by longer). To get the tangent, divide the sine by the cosine.
Let's go:
[tex]sinC = \frac{7}{25}\\~\\cosC = \frac{24}{25}\\~\\tanC = \frac{7}{25} / \frac{24}{25} = \frac{7}{24}[/tex]
Answer:
sin(7/25), cos(24/25), tan(7/24)
Step-by-step explanation:
The sin, cos, and tan are found through the sides of the triangle.
The acronym SOH CAH TOA can be used to find which goes where.
S = sin
C = cos
T = tan
O = opposite
A = adjacent
H = hypotenuse
since it asks to use angle C you start from there, for sin its O/H hint by the SOH the rest are the same.