Answer:
750 g of CO₂
Explanation:
The balanced equation for the reaction is given below:
C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O
Next, we shall determine the mass of C₃H₈ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:
Molar mass of C₃H₈ = (12×3) + (8×1)
= 36 + 8 = 44 g/mol
Mass of C₃H₈ from the balanced equation = 1 × 44 = 44 g
Molar mass of CO₂ = 12 + (16×2)
= 12 + 32 = 44 g/mol
Mass of CO₂ = 3 × 44 = 132 g
SUMMARY:
From the balanced equation above,
44 g of C₃H₈ reacted to produce 132 g of CO₂.
Finally, we shall determine the mass of CO₂ produced by the reaction of 250 g of C₃H₈. This can be obtained as follow:
From the balanced equation above,
44 g of C₃H₈ reacted to produce 132 g of CO₂.
Therefore, 250 g of C₃H₈ will react to produce = (250 × 132)/44 = 750 g of CO₂.
Thus, 750 g of CO₂ were obtained from the reaction.
The number of grams of carbon dioxide should be 750 grams.
Since
The balanced equation for the reaction is
C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O
Now
Molar mass of C₃H₈ = (12×3) + (8×1)
= 36 + 8 = 44 g/mol
Hence, Mass of C₃H₈ from the balanced equation = 1 × 44 = 44 g
Now
Molar mass of CO₂ = 12 + (16×2)
= 12 + 32 = 44 g/mol
Hence, Mass of CO₂ = 3 × 44 = 132 g
Now the no of grams should be
= (250 × 132)/44
= 750 g of CO₂.
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