Respuesta :
Answer:
2 square cm
Step-by-step explanation:
Given :
A square is inscribed in a circle whose radius is r = 1 cm
Therefore, the diameter of the circle is 2 r = 2 x 1
= 2 cm.
So the diagonal of the square is 2r.
Using the Pythagoras theorem, we find each of the side of the triangle is [tex]$r \sqrt 2$[/tex].
Therefore, the area of the square is given by [tex]$\text{(side)}^2$[/tex]
= [tex]$(r\sqrt 2)^2$[/tex]
[tex]$= 2 r^2$[/tex]
[tex]$= 2 (1)^2$[/tex]
[tex]$=2 \ cm^2$[/tex]
Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.
