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A 12.0 volt battery is connected in a series to 4 identical 5.00 ohm resistors connected in parallel to each other. What is the current through the battery?

Respuesta :

Snoopycatlover

Answer:

R =4•Rₒ = 4•50 = 200 Ω

Ohm’s law

I =U/R = 12/200 =0.06 A

thanoscaptain00

Answer:

9.6 Amperes

Explanation:

  1. since the resistors are connected in parallel connection the equivalent resistance is

1/R = 1 /5 + 1/5 + 1/5 + 1/5

solving for R we get 5/4 ohms

then from V=IR

I = V/R

I=12/(5/4)

hence I= 9.6 Amperes

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