Answer:
The energy stored is: 62.5 Joules
Explanation:
Given
[tex]k = 500N/m[/tex] --- spring constant
[tex]x = 0.5m[/tex] --- stretch
Required
The amount of energy
This is calculated as:
[tex]U = \frac{1}{2} kx^2[/tex]
[tex]U = \frac{1}{2} * 500N/m * (0.5m)^2[/tex]
[tex]U = 250N/m * (0.5m)^2[/tex]
[tex]U = 62.5\ J[/tex]