Answer: [tex]y=-\frac{3}{2}x+12[/tex]
Step-by-step explanation:
To find the equation of line B, we need to find the slope first, then the y-intercept. We first want to convert line A into slope-intercept form, so we can find the slope.
[tex]3x+2y=10[/tex] [subtract both sides by 3x]
[tex]2y=10-3x[/tex] [divide both sides by 2]
[tex]y=5-\frac{3}{2}x[/tex]
With the slope-intercept form of line A, we can see that the slope is [tex]-\frac{3}{2}[/tex]. We take the slope and the given point (4,6) to find the y-intercept of line B.
[tex]y=-\frac{3}{2}x+b[/tex] [plug in (4,6)]
[tex]6=-\frac{3}{2}(4)+b[/tex] [multiply]
[tex]6=-6+b[/tex] [add both sides by 6]
[tex]b=12[/tex]
With the y-intercept, we know the equation for line B is [tex]y=-\frac{3}{2}x+12[/tex].
