Answer:
10[tex]\pi[/tex]/9 -8[tex]\pi[/tex]/9
Step-by-step explanation:
the question is asking, how many times around a circle is 44[tex]\pi[/tex] / 9 times so we know 2[tex]\pi[/tex] is once around. Then how many 2s are in 44/9th ??
9*4 = 36 so subtract 36 from 44 , you get 8 and we also went around 2 times b/c 4[tex]\pi[/tex] means we went all the way around the circle 2 times, see?
the 4 is that part of 4*9 to get the 36. well I hope you understand what i'm trying to explain, ask if you don't.
so we've got 8[tex]\pi[/tex]/9 left over after going around twice. so then go 8/9 more. this is 1/8 short of [tex]\pi[/tex]. The negative sign means we've been traveling in a clock wise direction. so we're 1/8 short of making it to [tex]\pi[/tex] but in the III quadrant. so past [tex]\pi[/tex] by 1/8 if we go in the counter clockwise direction to find our coterminal angle. That is. we are at 10[tex]\pi[/tex]/ 9. They made this problem very difficult. what class is this for. also we are at - 8[tex]\pi[/tex] / 9 ... if you want to come around the circle from the other way. Got it... :D, I don't quite understand either and i'm the one explaining it.. :D :D
