Answer:
0.04 L (or 40 mL)
Explanation:
The dilution equation is: [tex]M_{s} V_{s} = M_{d} V_{d}[/tex]
[tex]M_{s}[/tex] = the molarity of the sock solution
[tex]V_{s}[/tex] = the volume of the sock solution
[tex]M_{d}[/tex] = the molarity of the diluted solution
[tex]V_{d}[/tex] = the volume of the diluted solution
We are given the original, or stock, solution, which is [tex]M_{s} = 7.00 M NaOH[/tex], and [tex]V_{s} = 0.02 L (20 mL)[/tex]. We are also given the final molarity, which is: [tex]M_{d} = 3.5 M NaOH[/tex].
So, plugging our given into the dilution equation, results in:
[tex]7.00 M * 0.02 L = 3.5M * V_{d}[/tex] (divide both sides by 3.5 M, in order to get [tex]V_{d}[/tex] by itself).
[tex]\frac{7.00 M * 0.02 L}{3.5M} = V_{d}[/tex]
[tex]V_{d} = 0.04 L (or 40 mL)[/tex]
So, the final volume of a 3.5 M NaOH solution, with an original solution of 20 mL of a 7.00 M NaOH solution, is 0.04 L (or 40 mL)
Hopefully this helped. Good luck!
