Answer:
(3, 0 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c (a ≠ 0 )
Then the x- coordinate of the vertex is
[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]
y = 5x² - 30x + 45 ← is in standard form
with a = 5, b = - 30 , then
[tex]x_{vertex}[/tex] = - [tex]\frac{-30}{10}[/tex] = 3
Substitute x = 3 into the function for corresponding value of y
y = 5(3)² - 30(3) + 45 = 45 - 90 + 45 = 0
vertex = (3, 0 )
Answer:
Vertex is (3,0)
Step-by-step explanation:
Given y= 5x^2 - 30x + 45
y = 5 ( x^2 - 6x + 9)
= 5 ( x -3 )^ 2 + 0
Standard formula of parabola is y = a(x - k)^2 + k where vertex is (h,k)
Here, h = 3 and k = 0
So, Vertex is ( 3, 0)
