Answer:
the molecular formula of a compound is P₄O₁₀.
M(P₂O₅) = 2 · Ar(P) + 5 · Ar(O) · g/mol.
M(P₂O₅) = 2 · 31 + 5 · 16 · g/mol.
M(P₂O₅) = 142 g/mol; molar mass of empirical formula.
M(PₓOₙ) = 284 g/mol; molecular mass of unknown compound.
M(PₓOₙ) : M(P₂O₅) = 284 g/mol : 142 g/mol.
M(PₓOₙ) : M(P₂O₅) = 2 : 1.
Explanation:
The empirical formula is [tex]P_{2}O_{5}[/tex] and The molecular formula is [tex]P_{4}O_{10}[/tex]
[tex](\frac{47.3g}{1})( \frac{1 mol}{30.97g})= 1.41 moles[/tex] of Phosphorus.
[tex](\frac{56.3}{1})(\frac{1 mol}{16}) = 3.51 moles[/tex] of Oxygen
3.51/1.41 = 2.49 (rounded off 2.5)
1.41/1.41 = 1
2.5 *2 = 5 (Oxygen)
2 *1 = 2 (Phosphorus)
Hence [tex]P_{2}O_{5}[/tex] is Empirical formula
and [tex]P_{4}O_{10}[/tex] is Molecular Formula
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