Answer:
[tex]1190\ \text{mL}[/tex]
Explanation:
[tex]M_1[/tex] = Initial Concentration of KCl = 2.7 M
[tex]V_1[/tex] = Volume of KCl = 1 M
[tex]M_2[/tex] = Final concentration of KCl = 1 M
[tex]V_2[/tex] = Amount of water
We have the relation
[tex]M_1V_1=M_2V_2\\\Rightarrow V_2=\dfrac{M_1V_1}{M_2}\\\Rightarrow V_2=\dfrac{2.7\times 700}{1}\\\Rightarrow V_2=1890\ \text{mL}[/tex]
The amount of water that is to be added is [tex]1890-700=1190\ \text{mL}[/tex].
