Given:
The expression is:
[tex]\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)[/tex]
To find:
The missing values in the simplification of the given expression.
Solution:
We have,
[tex]\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)[/tex]
Combining like terms, we get
[tex]\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)=\left(\dfrac{6}{17}t+\dfrac{7}{17}t\right)+\left(-6+9\right)[/tex]
[tex]\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)=\dfrac{13}{17}t+3[/tex]
Therefore, the missing values for 1,2,3,4 blanks are [tex]\dfrac{6}{17}t,9,\dfrac{13}{17},3[/tex] respectively.
