Answer:
[tex][C]=0.0221M[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction at equilibrium:
[tex]3A\rightleftharpoons 3B+2C[/tex]
It is possible for us to set up the equilibrium expression as shown below:
[tex]Kc=\frac{[B]^3[C]^2}{[A]^3}[/tex]
Whereas Kc, [A] and [B] are known as 0.0091, 0.031M and 0.0823M and it is required to calculate [C]; thus, we solve for it as follows:
[tex][C]^2=\frac{[A]^3Kc}{B]^3}[/tex]
[tex][C]=\sqrt{\frac{(0.031)^3*0.0091}{(0.0823)^3}}[/tex]
[tex][C]=0.0221M[/tex]
Best regards!
