If the radius of a right circular cylindrical oil can base is 4 inches and its height is 11 inches, then the surface area of that right circular cylindrical oil can is 376.99 square inches.
What is the surface area of a right circular cylindrical figure?
Let b and h be the radius of the base and height of a right circular cylindrical figure respectively. Then the surface area of this right circular cylindrical figure is 2πb(b + h).
How to solve this problem?
Given that the radius of the base of the can is 4 inches.
The height of the can is 11 inches.
Then the surface area of the can = 2π * 4(4 + 11) = 8π(15) = 120π = 376.99 square inches
Therefore, If the radius of a right circular cylindrical oil can base is 4 inches and its height is 11 inches, then the surface area of that right circular cylindrical oil can is 376.99 square inches.
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