Answer:
The nth term is: [tex]a_n = \frac{1}{4} + \frac{1}{4}(n-1)[/tex]
a40 = 10
Step-by-step explanation:
Arithmetic sequence:
In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.
The nth term of a sequence is given by:
[tex]a_n = a_1 + (n-1)d[/tex]
In which [tex]a_1[/tex] is the first term and d is the common difference.
1/4,1/2
This means that:
[tex]d = \frac{1}{2} - \frac{1}{4} = \frac{2}{4} - \frac{1}{4} = \frac{1}{4}[/tex]
1/4
This means that [tex]a_1 = \frac{1}{4}[/tex]
The nth term is:
[tex]a_n = a_1 + (n-1)d[/tex]
[tex]a_n = \frac{1}{4} + \frac{1}{4}(n-1)[/tex]
Then find a40.
[tex]a_{40} = \frac{1}{4} + \frac{1}{4}(40-1) = \frac{1}{4} + \frac{39}{4} = \frac{40}{4} = 10[/tex]
So
a40 = 10
