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The sum of the length and width of a rectangle is more than 15 units. The length is 3 units more than the width, x. Which model and solution is correct for this situation?

Respuesta :

Answer: [tex]6, 9\ \text{units}[/tex]

Step-by-step explanation:

Given

The Sum of length and width is [tex]15\ units[/tex]

length is 3 units more than the width

width is [tex]x[/tex]

length is [tex]x+3[/tex]

Their sum is 15

[tex]\Rightarrow x+x+3=15\\\Rightarrow 2x=12\\\Rightarrow x=6\ \text{units}[/tex]

Length is [tex]x+3=9\ \text{units}[/tex]

Width is  [tex]x=6\ \text{units}[/tex]

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