1250m²
Rectangle
perimeter=2(L+B)
2(L+B)=250.....equ(1)
Area= L×B
L×B=2500......equ(2)
Solving simultaneously by direct substitution
from equ (1) L=125-B
substituting it's value into equ (2) gives that (125-B)B=2500
125B-B²=2500
solving quadratically gives B1= 100m B2=25m
substituting it's value in equ (1) gives L1= 25m L2=100m
when the rectangular field is cut diagonally into two halves then we have two right angled triangle
area of a triangle=½B×H=½L×B
then we have ½×100×25= 1250m² for each triangle.