Ill give brainliest - please help ASAP
WITH THE WORK THO PLEASE?

Answer:
<KLU=½(arc KL+arc UM)=½(165+65)=115°
2.
<EFG=½(arc EF+arc PD)
128=½(206+arc PD)
arc PD=128×2-206=50°
3.
<SQR=½(arc(SR+TU))=½(51+165)=108°
4/
<MkL=½(arc(LM+QN)
105×2=155+arc QN
arc QN=210-155=55°
Step-by-step explanation:
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