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A rope attached to an engine pulls a 250 N crate up an 18.0° ramp at constant speed. The coefficient of kinetic friction for the surfaces of the crate and ramp is 0.26. What is the magnitude of the force that the rope exerts on the crate parallel to the ramp? (9.81 ms)

Respuesta :

abidemiokin

Answer:

307.07N

Explanation:

Given

Weight of object = 250N

angle of elevation  = 18.0°

coefficient of kinetic friction n = 0.26

acceleration = 9.81m/s^2

Required

Force parallel to the ramp

Using Newton second law

F = ma

Fm - Ff = ma

Fm - nR = ma

Fm = ma +nR

Fm = 25(9.81) + 0.26(Wcostheta)

Fm = 25(9.81) + 0.26(250cos18)

Fm = 245.25+61.81

Fm = 307.07N

Hence he magnitude of the force that the rope exerts on the crate parallel to the ramp is 307.07N

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