The distance between the y-intercept of f(x) = x^2 + 7x - 18 and the y-intercept of the table is 23 units
How to determine the distance?
The function f(x) is given as:
f(x) = x^2 + 7x - 18
The y-intercept is when x = 0.
So, we have:
f(0) = 0^2 + 7(0) - 18
Evaluate
f(0) = -18
For the table, start by calculating the slope (m)
m = 11 - 2/10 + 5
m = 0.6
The y-intercept is then calculated using:
b = y - mx
So, we have:
b = 11 - 0.6 * 10
Evaluate
b = 5
This means that:
y-intercept = 5
The difference between both values is:
Difference = |-18- 5|
Evaluate
Difference = 23
Hence, the distance between the y-intercept of f(x) = x^2 + 7x - 18 and the y-intercept of the table is 23 units
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