The length of the stretched wire is 17.34 feet.
The cosine of an angle is: The length of the adjacent side divided by the length of the hypotenuse.
According to the given question.
The length between the base of the pole where the wire meets the ground is 15 feet.
And the length of the stretched wire is L.
Also, angle between the stretched wire and the base = 30 degrees.
Now, in the given figure, the cosine of 30 degree is given by
[tex]cos30 = \frac{15}{L}[/tex]
⇒[tex]\frac{\sqrt{3} }{2}= \frac{15}{L}[/tex]
⇒[tex]L = \frac{15(2)}{\sqrt{3} }[/tex]
⇒[tex]L = \frac{30}{1.73}[/tex]
⇒[tex]L = 17.34[/tex] feet
Hence, the length of the stretched wire is 17.34 feet.
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