Respuesta :
Answer:
The p-value of the test is 0.5028>0.05, which means that there is sufficient evidence to determine that 68% represents the state in question.
Step-by-step explanation:
Test if 68% represents the state in question.
This means that at the null hypothesis, we test if the proportion is 68%, that is:
[tex]H_0: p = 0.68[/tex]
At the alternate hypothesis, we test if the proportion is different of 68%, that is:
[tex]H_a: p \neq 0.68[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
0.68 is tested at the null hypothesis:
This means that [tex]\mu = 0.68, \sigma = \sqrt{0.68*0.32}[/tex]
32 of the 44 online courses at this particular community college were taught by full-time faculty.
This means that [tex]n = 44, X = \frac{32}{44} = 0.7273[/tex]
Test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{0.7273 - 0.68}{\frac{\sqrt{0.68*0.32}}{\sqrt{44}}}[/tex]
[tex]z = 0.67[/tex]
P-value of the test and decision:
The p-value of the test is the probability of finding a sample proportion differing by the population proportion by at least 0.7273 - 0.68 = 0.0473, which is P(|z| > 0.67), which is 2 multiplied by the p-value of z = -0.67.
Looking at the z-table, z = -0.67 has a p-value of 0.2514
2*0.2514 = 0.5028
The p-value of the test is 0.5028>0.05, which means that there is sufficient evidence to determine that 68% represents the state in question.
