contestada

Consider the following code segment.
int[][] arr = {{3, 2, 1}, {4, 3, 5}};
for (int row = 0; row < arr.length; row++)
{
for (int col = 0; col < arr[row].length; col++)
{
if (col > 0)
{
if (arr[row][col] >= arr[row][col - 1])
{
System.out.println("Condition one");
}
}
if (arr[row][col] % 2 == 0)
{
System.out.println("Condition two");
}
}
}
As a result of executing the code segment, how many times are "Condition one" and "Condition two" printed?
A. "Condition one" is printed twice, and "Condition two" is printed twice.
B. "Condition one" is printed twice, and "Condition two" is printed once.
C. "Condition one" is printed once, and "Condition two" is printed twice.
D. "Condition one" is printed once, and "Condition two" is printed once.
E. "Condition one" is never printed, and "Condition two" is printed once.

Respuesta :

MrRoyal

Answer:

C. "Condition one" is printed once, and "Condition two" is printed twice.

Explanation:

Given

The above code segment

Required

The number of times [tex]each\ print\ statement[/tex] is executed

For "Condition one" to be printed, the following conditions must be true:

if (col > 0) ---- the column must be greater than 0 i.e. column 1 and 2

if (arr[row][col] >= arr[row][col - 1]) --- the current element must be greater than the element in the previous column

Through the iteration of the array, the condition is met just once. When

[tex]row = 1[/tex]  and   [tex]col = 2[/tex]

[tex]arr[1][2] > arr[1][2-1][/tex]

[tex]arr[1][2] > arr[1][1][/tex]

[tex]4 > 3[/tex]

For "Condition two" to be printed, the following condition must be true:

if (arr[row][col] % 2 == 0) ----array element must be even

Through the iteration of the array, the condition is met twice. When

[tex]row = 0[/tex]  and   [tex]col = 1[/tex]

[tex]row = 1[/tex]  and   [tex]col = 0[/tex]

[tex]arr[0][1] = 2[/tex]

[tex]arr[1][0] = 4[/tex]

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