yeet this is a thicc problem...
6x - 14 + 3(2x-1) = 5 - 2(x-10)
first expand
6x - 14 + 6x -3 = 5 -2x-20
now put constants and variables on either sides of the thingamajig
6x+6x+2x= 5 - 20 + 3 + 14
14x = 2
x = 1/7
i deserve an award for that XD
The value x = 3 makes the given equation true.
Important information:
The given equation can be written as:
[tex]6x-14+6x-3=5-2x+20[/tex]
[tex]12x-17=-2x+25[/tex]
Isolate the variable.
[tex]12x+2x=25+17[/tex]
[tex]14x=42[/tex]
[tex]x=\dfrac{42}{14}[/tex]
[tex]x=3[/tex]
Therefore, the required value of x is 3.
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