Given :
A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker.
To Find :
The wavelength of the first (n = 1) interference minimum (destructive).
Solution :
Since speaker are identical so they are in same phase.
For first destructive construction difference between the distance should be equal to half the wavelength .
So, [tex]8-6 = \dfrac{\lambda}{2}\\\\\lambda = 4 \ m[/tex]
Frequency is given by :
[tex]\nu = \dfrac{343}{4}\ Hz\\\\\nu = 85.75 \ Hz[/tex]
Hence, this is the required solution.
