Answer:
[tex][CO]=[Cl_2]=0.01436M[/tex]
[tex][COCl_2]=0.00064M[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:
[tex]K=\frac{[CO][Cl_2]}{[COCl_2]}[/tex]
Which can be written in terms of x, according to the ICE table:
[tex]0.32=\frac{x^2}{0.015M-x}[/tex]
Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:
[tex][CO]=[Cl_2]=0.01436M[/tex]
[tex][COCl_2]=0.015M-0.01436M=0.00064M[/tex]
Regards!
