Answer:
65ᵗʰ Term of the sequence is 479
50ᵗʰ Term of the sequence is 346
Step-by-step explanation:
1.)
Here,
First Term = a₁ = 3
Second Term = a₂ = 10
Third Term = a₃ = 17
Now,
Common Difference (d)
d = a₂ - a₁ = (-7) - (-15) = -7 + 15 = 8
d = a₃ - a₂ = 1 - (-7) = 1 + 7 = 8
Here, Common Difference is same everywhere
Now, For 65ᵗʰ term, n = 65
aₙ = a + (n - 1)d
a₆₅ = (-15) + (65 - 1) × 8
a₆₅ = (-15) + 64 × 8
a₆₅ = (-15) + 512
a₆₅ = 479
Thus, 65ᵗʰ Term of the sequence is 479
2.)
Here,
First Term = a₁ = -15
Second Term = a₂ = -7
Third Term = a₃ = 1
Now,
Common Difference (d)
d = a₂ - a₁ = 10 - 3 = 7
d = a₃ - a₂ = 17 - 10 = 7
Here, Common Difference is same everywhere
Now, For 50ᵗʰ term, n = 50
aₙ = a + (n - 1)d
a₅₀ = 3 + (50 - 1) × 7
a₅₀ = 3 + 49 × 7
a₅₀ = 3 + 343
a₅₀ = 346
Thus, 50ᵗʰ Term of the sequence is 346
-TheUnknownScientist
