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Samuel hits a ball, which is initially at rest, off of a tee. What is the velocity of the ball after it is hit, if Samuel applies 30 J of work to the 1.1 kg ball? It will be helpful to show your work on a separate sheet of paper.

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asuwafohjames

Answer:

7.39 m/s

Explanation:

Applying

K.E = 1/2mv²..................... Equation 1

Where K.E = Kinetic Energy, m = mass of the ball, v = velocity of the ball.

Make v the subject of the equation

v = √(2K.E/m)................. Euqation 2

From the question,

Given: K.E = 30 J, m = 1.1kg

Substitute these values into equation 2

v = √(2×30/1.1)

v = √54.54

v = 7.39 m/s

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