Respuesta :
The complete question is as follows: How many moles of a gas at 100 c does it take to fill a 1.00 l flask to a pressure of 152kPa
Answer: There are 0.0489 moles of a gas at [tex]100^{o}C[/tex] is required to fill a 1.00 l flask to a pressure of 152kPa.
Explanation:
Given: Volume = 1.00 L,
Pressure = 152 kPa (1 kPa = 1000 Pa) = 152000 Pa
Convert Pa into atm as follows.
[tex]1 Pa = 9.86 \times 10^{-6} atm\\152000 Pa = 152000 \times \frac{9.86 \times 10^{-6}atm}{1 Pa}\\= 1.5 atm[/tex]
Temperature = [tex]100^{o}C = (100 + 273) K = 373 K[/tex]
Using the ideal gas formula as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
[tex]PV = nRT\\1.5 atm \times 1.0 L = n \times 0.0821 L atm/mol K \times 373 K\\n = \frac{1.5 atm \times 1.0 L}{0.0821 L atm/mol K \times 373 K}\\n = 0.0489 mol[/tex]
Thus, we can conclude that there are 0.0489 moles of a gas at [tex]100^{o}C[/tex] is required to fill a 1.00 l flask to a pressure of 152kPa.
