Answer: 5 ft
Step-by-step explanation:
Given
The path of the swimmer is given by
[tex]h=-0.1d^2+0.1d+3[/tex]
The swimmer can go horizontally depends upon the depth
So, find the maximum depth by taking derivative w.r.t height
[tex]h'=-0.2d+0.1[/tex]
Put derivative equal to 0
[tex]\Rightarrow -0.2d+1=0\\\\\Rightarrow d=\dfrac{1}{0.2}\\\\\Rightarrow d=5\ ft[/tex]
thus, the swimmer can go up to a distance of 5 ft.