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The pressure of a tire is 200kPa at a temperature of 27 C. On a hot sunny day, the pressure
rises to 223 kPa. What is the temperature of the air in the tire?

Respuesta :

Trancescient

Explanation:

T1 = 27C + 273 = 300K

P1 = 200 kPa

P2 = 223 kPa

T2 = ?

According to Gay-Lussac's law:

P1/T1 = P2/T2

(200 kPa/300 K) = (223 kPa/T2)

T2 = (223 kPa/200 kPa)(300 K)

= 334.5 K

= 61.5°C

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