Complete the square to write each equation in vertex form. Then, state whether the vertex is a minimum or a maximum and give its coordinates.

Answer:
Step-by-step explanation:
[tex]y=x^2+2x-2\\\\y=x^2+2x+1-1-2\\\\\bold{y=(x+1)^2-3}[/tex]
a = 1 > 0 ← it means the parabla opens up, so, the vertex is minimum
The vertex form is y = a(x - h)² + k, where (h, k) is the vertex
So, from y = (x + 1)² - 3 the vertex is: (-1, -3)