Answer:
vertex form: y = (x + 3)² + 1
the vertex is minimum
coordinates of the vertex: (-3, 1)
Step-by-step explanation:
[tex]y=x^2+6x+10\\\\y=x^2+6x+9-9+10\\\\\bold{y=(x+3)^2+1}[/tex]
a = 1 > 0 ← it means the parabla opens up, so, the vertex is minimum
The vertex form is y = a(x - h)² + k, where (h, k) is the vertex
So, from y = (x + 3)² + 1 the vertex is: (-3, 1)
