an object decelerate uniformly from 60.0m/s to a stop in 10.0s what is it acceleration?
a. 6.0m/S2
b. -6.0/S2
c.600m/S2
d.-600m/S2

Respuesta :

Answer:

I'm not 100% sure, but I think its a. 6.0m/s2

Formula=(v-u)/t
(0-60)/10= -6.0m/s