The numerical value of the density of a nucleus of atomic number A is determined as 2.29 x 10¹⁷ kg/m³.
Density of the nucleus
The density of the nucleus of atomic number A is calculated as follows;
ρ = m/V
where;
- m is mass of the atom = 1.66 x 10⁻²⁷ kg
- r is radius of the atom = 1.2 x 10⁻¹⁵ m
[tex]\rho = \frac{m}{V} \\\\\rho = \frac{m}{\frac{4}{3} \pi r^3} \\\\\rho = \frac{1.66 \times 10^{-27}}{\frac{4}{3} \pi (1.2 \times 10^{-15})^3} \\\\\rho = 2.29 \times 10^{17} \ kg/m^3[/tex]
Thus, the numerical value of the density of a nucleus of atomic number A is determined as 2.29 x 10¹⁷ kg/m³.
The complete question is below:
find the numerical value of the density of a nucleus of atomic number A with a radius of 1.2 x 10⁻¹⁵ m and mass of 1.66 x 10⁻²⁷ kg.
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