Answer:
x = 1
Step-by-step explanation:
For a quadratic function [tex]f(x)=ax^2+bx+c[/tex], the axis of symmetry is
[tex]x=-\frac{b}{2a}[/tex].
This comes from using part of the Quadratic Formula for finding zeros of the function:
[tex]x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} = \frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}[/tex]
See the -b/(2a) in the first term? That's the x-coordinate of the vertex (turning point) of the parabolic graph of the function. The axis of symmetry goes through the vertex.
