Answer:
The magnitude of the gravitational force which the astronaut experience in satellite [tex]= 448[/tex] Newton
Explanation:
As we know
Gravitational force F = [tex]\frac{GMm}{r^2}[/tex]
Where G is the gravitational constant [tex]6.67 * 10^{-11}[/tex]
M is the mass of earth [tex]= 6* 10^{24}[/tex]
m is not given
r is the radius of earth [tex]6 400*10^3[/tex]
Substituting the given values, we get -
[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3)^2}[/tex]
[tex]m = 71.6[/tex] Kg
Gravitational force in the satellite
[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3 + 1600 *10^3)^2}\\F = 448[/tex]N
