Answer:
width = 10 yds
Step-by-step explanation:
perimeter = 2L + 2W
74 = 2(27) + 2W
74 = 54 + 2W
subtract 54 from both sides of the equation:
2W = 20
divide both sides by 2:
W = 10
The width of the yard whose length is 27 yards and perimeter is 74 yards is evaluated to be 10 yards
For a rectangle with length and width L and W units, we get:
Perimeter of the rectangle = [tex]2(L + W) \: \rm units[/tex]
For this case, let we assume that:
The width of the considered rectangular field = W yards
Then, as we're provided that:
Putting these in the formula for perimeter of a rectangle, we get;
[tex]Perimeter = 2( L + W)\\74 = 2(27 + W)\\\\\text{Dividing both the sides by 2}\\\\\dfrac{74}{2} = \dfrac{2(27+W)}{2}\\\\37 = 27 + W\\\\\text{Subtracting 27 from both the sides}\\\\37 - 27 = W\\W = 10 \: \rm yards[/tex]
Thus, the width of the yard whose length is 27 yards and perimeter is 74 yards is evaluated to be 10 yards
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