Answer:
the required tension is 4.57 N.
Explanation:
Given;
first velocity of the wave, v₁ = 24 m/s
first tension on the string, T₁ = 5.34 N
second velocity of the wave, v₂ = 22.2 m/s
second tension of the string, T₂ = ?
[tex]v = \sqrt{\frac{T}{\mu} }[/tex]
where;
μ is mass per unit length
[tex]v^2 =\frac{T}{\mu} \\\\\mu = \frac{T}{v^2} = \frac{T_1}{v_1^2} = \frac{T_2}{v_2^2} \\\\T_2 =\frac{T_1v_2^2}{v_1^2} \\\\T_2 = \frac{5.34 \times 22.2^2}{24^2} \\\\T_2 = 4.57 \ N[/tex]
Therefore, the required tension is 4.57 N.
