Answer:
"109" will be the appropriate response.
Step-by-step explanation:
The given values are:
Standard deviation,
[tex]\sigma=18.4[/tex]
Margin of error,
[tex]E = 4.1[/tex]
Using the table,
[tex]Z_{(\frac{0.02}{2} )}=2.326[/tex]
Now,
The sample size will be:
⇒ [tex]n=(\frac{Z_{(\frac{0.02}{2})\times \sigma}}{E} )^2[/tex]
On substituting the values, we get
⇒ [tex]=(\frac{2.326\times 18.4}{4.1} )^2[/tex]
⇒ [tex]=(\frac{42.7984}{4.1} )^2[/tex]
⇒ [tex]=(10.4386341)^2[/tex]
⇒ [tex]=109[/tex]
