Answer: 48
Step-by-step explanation:
Given
Trapezoid DEFG is dilated by a scale factor of [tex]\frac{2}{3}[/tex]
[tex]E'F'=32[/tex]
Suppose the length of EF is [tex]x[/tex]
Multiply the side length of DEFG by [tex]\frac{2}{3}[/tex] to form E'F'
[tex]\Rightarrow E'F'=x\times \dfrac{2}{3}\\\\\Rightarrow 32=x\times \dfrac{2}{3}\\\\\Rightarrow x=16\times 3\\\Rightarrow x=48[/tex]
[tex]\therefore EF=48[/tex]
