Answer:
Al(OH)3 (s) + 3H+ (aq) → 3H2O (l) + Al3+ (aq)
Explanation:
The net ionic equation for the reaction between solid Al(OH)₃ and aqueous nitric acid, HNO₃ is
The reaction between Al(OH)₃ and HNO₃ will proceeds as follow:
HNO₃ (aq) —> H⁺(aq) + NO₃¯(aq)
HNO₃ (aq) + Al(OH)₃ (s) —>
H⁺(aq) + NO₃¯(aq) + Al(OH)₃ (s) —> H₂O(l) + NO₃¯(aq) + Al³⁺(aq)
Cancel the spectator ion (i.e NO₃¯)
H⁺(aq) + Al(OH)₃ (s) —> H₂O(l) + Al³⁺(aq)
Write 3 before H⁺ and H₂O to obtain the balanced ionic equation as shown below:
3H⁺(aq) + Al(OH)₃ (s) —> 3H₂O(l) + Al³⁺(aq)
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