Given :
A 2kg object is moving with speed 5m/s. then hits a wall in 0.5s before reversing its direction with a speed of 2m/s.
To Find :
The impulse.
Solution :
Impulse can be calculated by change in momentum :
[tex]I = mv_f - mv_i\\\\I = 2\times( -2 + 5 )\ kg \ m/s\\\\I = 6 \ kg \ m/s[/tex]
Therefore, the impulse is 6 kg m/s.
