Given:
The equation is:
[tex]\ln(3x^2-1)=\ln(191)[/tex]
To find:
The solution for the given equation.
Solution:
We have,
[tex]\ln(3x^2-1)=\ln(191)[/tex]
On comparing both sides, we get
[tex]3x^2-1=191[/tex]
[tex]3x^2=191+1[/tex]
[tex]3x^2=192[/tex]
Divide both sides by 3.
[tex]x^2=\dfrac{192}{3}[/tex]
[tex]x^2=64[/tex]
Taking square root on both sides, we get
[tex]x=\pm \sqrt{64}[/tex]
[tex]x=\pm 8[/tex]
Therefore, the solutions of the given equation are -8 and 8.
