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The height of a javelin after it has left the hand of the thrower can be modeled by the function h=3(4t-2)-t + 4), where h is the height of the javelin and t is the time in seconds. How long is the javelin in the air?

Respuesta :

mhanifa

Answer:

  • 3.5 seconds

Step-by-step explanation:

Given function:

  • h(t) = 3(4t - 2)(- t + 4)

The time the javelin is in the air is the difference of zero's of the function:

  • 3(4t - 2)(- t + 4) = 0
  • (4t - 2)(- t + 4)
  • 4t - 2 = 0 ⇒ t = 0.5
  • -t + 4 = 0 ⇒ t = 4

Time in the air:

  • 4 - 0.5 = 3.5 seconds

It is better visible on the graph

Ver imagen mhanifa

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