Answer:
[tex]y=\frac{3}{2} x-6[/tex]
Step-by-step explanation:
Hi there!
What we need to know:
1) Determine the slope of the parallel line
Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.
[tex]3x = 2y[/tex]
Switch the sides
[tex]2y=3x[/tex]
Divide both sides by 2 to isolate y
[tex]\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x[/tex]
Now that this equation is in slope-intercept form, we can easily identify that [tex]\frac{3}{2}[/tex] is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope [tex]\frac{3}{2}[/tex] . Plug this into [tex]y=mx+b[/tex]:
[tex]y=\frac{3}{2} x+b[/tex]
2) Determine the y-intercept
[tex]y=\frac{3}{2} x+b[/tex]
Plug in the given point, (4,0)
[tex]0=\frac{3}{2} (4)+b\\0=6+b[/tex]
Subtract both sides by 6
[tex]0-6=6+b-6\\-6=b[/tex]
Therefore, -6 is the y-intercept of the line. Plug this into [tex]y=\frac{3}{2} x+b[/tex] as b:
[tex]y=\frac{3}{2} x-6[/tex]
I hope this helps!
