Q)A certain mass of gas occupies a volume 2.5 L at 90atm. What pressure would the gas exert if it were placed in a 10 L container at the same temperatur?​

Respuesta :

Answer:

23 atm

Explanation:

Step 1: Given data

  • Initial volume (V₁): 2.5 L
  • Initial pressure (P₁): 90 atm
  • Final volume (V₂): 10 L
  • Final pressure (P₂): ?

Step 2: Calculate the final pressure of the gas

If we assume constant temperature and ideal behavior, we can calculate the final pressure of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁ / V₂

P₂ = 90 atm × 2.5 L / 10 L = 23 atm

As expected, since the volume increased, the pressure decreased.